4p^2=120+4p

Solution for 4p^2=120+4p equation:

4p^2=120+4p

We move all terms to the left:

4p^2-(120+4p)=0

We add all the numbers together, and all the variables

4p^2-(4p+120)=0

We get rid of parentheses

4p^2-4p-120=0

a = 4; b = -4; c = -120;
Δ = b2-4ac
Δ = -42-4·4·(-120)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*4}=\frac{-40}{8}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*4}=\frac{48}{8}
=6
$